2.32y^2+.83y-9.59=0

Solution for 2.32y^2+.83y-9.59=0 equation:

2.32y^2+.83y-9.59=0

a = 2.32; b = .83; c = -9.59;
Δ = b2-4ac
Δ = .832-4·2.32·(-9.59)
Δ = 89.6841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(.83)-\sqrt{89.6841}}{2*2.32}=\frac{-0.83-\sqrt{89.6841}}{4.64}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(.83)+\sqrt{89.6841}}{2*2.32}=\frac{-0.83+\sqrt{89.6841}}{4.64}
$